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Next: Solution for D=3 Up: Path Integral Previous: The Pseudotime Displacement

Solution for D=2 H atom System

First we observe that the kinetic pseudoenergy has scale dimensions which is precisely opposite to that of the potential term, . This is the same dimensional situation as in the harmonic oscillator, where the dimensions are and , respectively. We therefore decide to go over to ``square root coordinates'' via some transformation which changes [11]. In two dimensions, the appropriate square root is given by the Levi-Cività transformation

 

We may imagine the vectors to move in the complex planes . Then the new variables u corresponds to the complex square root,

 

Let us also introduce the matrix

 

and write (74) as a matrix equation

 

In contrast to the three-dimensional case to be treated below we note here the rather obvious fact that the Levi-Cività mapping, which is simply a transformation to parabolic coordinates, carries the flat space into a flat space. Indeed, from (74) we have the infinitesimal transformation with the basis dyad

 

and the reciprocal dyad

 

We therefore find for the connection,

 

the matrix elements as follows

 

Notice that the connection satisfies an important identity

 

which is seen to be a consequence of the defining relation

 

together with the obvious identity

 

and the diagonal property of . It can be shown quie generally that this is the essential reason for the absence of the time slicing corrections to be proved in this section.

Both, torsion and Cartan curvature tensor vanish identically, the latter due to the linearity of the basis dyads in , which guarantees trivially the integrability conditions

 

and thus In the continuum limit it is easy to see that the Levy-Cività transformation converts the action (73) into that of a harmonic oscillator. With

 

we find

 

Apart from the trivial term , this is the action of a harmonic oscillator,

 

which oscillates in the pseudotime s with an effective mass

 

and a pseudofrequency

 

Note that this has the same dimension as pseudotime s corresponding to (in contrast to usual frequencies with ).

The path integral is well defined only as long as the energy E of the H atom is negative, i.e., in the bound-state regime. The amplitude in the continuum regime with positive E will be obtained by analytic continuation.

In the regularized form we can now calculate the pseudotime sliced amplitude. Taking for the splitting parameter and ignoring, for a moment, all complications due to the finite time slicing, we deduce from (66),

 

and hence

 

Writing the integrals over the 's in (71) as integrals over 's we see that the transformed amplitude (71) becomes simply

 

where denotes the time sliced oscillator amplitude

 

The integrals can all be done with the known result, in the limit ,

 

The symmetrization in in (94) is necessary since for each path from to there are two paths in the square-root space, one from to and one from to .

The fixed-energy amplitudes are obtained by integrating the pseudotime displacement amplitude over all S.

 

Inserting (96), this becomes

 

with the abbreviation

 

which is the one-dimensional fluctuation factor [see (2.145)]. The 's on the right-hand side are related to the 's on the left by

 

In doing the integral we have to circumnavigate the singularities in in accordance with the -prescription . This can be avoided by rotating the contour of S-integration so that it runs along the negative imaginary semi-axis,

This amounts to going over to the euclidean amplitude of the harmonic oscillator. The amplitude can be rewritten in a pleasant form by introducing further the variables

  

Then

 

 

and we obtain

 

This can be used to find the energy spectrum and the wave functions.

Notice that the integral converges only for . It is possible to write down another integral representation which converges for all . For this we change the variables of integration to

 

so that

 

This gives

 

The integrand has a cut in the complex -plane from z=-1 to and from to , with the integral running along the right-hand cut. This is transformed into an integral along a contour C which encircles the right-hand cut in the clockwise sense. Since the cut is of the type , we have the replacement rule

 

and obtain

 



next up previous
Next: Solution for D=3 Up: Path Integral Previous: The Pseudotime Displacement



Hagen Kleinert
Mon Jul 3 10:13:19 MET DST 1995